asyncio: event loop deep-dive

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← Cursos›Senior Deep-DivesMódulo 1 · Simultaneidade e aspectos internos assíncronos›asyncio: aprofundamento do loop de eventospredict3 / 161

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Tarefa🌐 shown in EN

📝 **Task:** Predict the 5-line interleave from `asyncio.gather(fetch('A', 1), fetch('B', 2))`. Both fetches print 'start NAME' first, then 'done NAME' after their await — and gather prints the result list last.

📋 Implement the function above. Tests run automatically.

💡 **Hint:** Re-read the theory if you get stuck.

Prevê a saída

Lê o código com atenção

import asyncio

async def fetch(name, delay):
    print(f"start {name}")
    await asyncio.sleep(delay)
    print(f"done {name}")
    return name

async def main():
    results = await asyncio.gather(
        fetch("A", 1),   # sleeps 1 s
        fetch("B", 2),   # sleeps 2 s
    )
    print(results)

asyncio.run(main())

# What does this print? Type your prediction.
# Hint: both fetches enter immediately (gather schedules them
# together). A finishes first (shorter sleep). The list at the end
# matches the ORDER the tasks were passed to gather, NOT the
# completion order.

O que o programa vai imprimir? Escreve aqui: