Lees de code zorgvuldig

import asyncio

async def fetch(name, delay):
    print(f"start {name}")
    await asyncio.sleep(delay)
    print(f"done {name}")
    return name

async def main():
    results = await asyncio.gather(
        fetch("A", 1),   # sleeps 1 s
        fetch("B", 2),   # sleeps 2 s
    )
    print(results)

asyncio.run(main())

# What does this print? Type your prediction.
# Hint: both fetches enter immediately (gather schedules them
# together). A finishes first (shorter sleep). The list at the end
# matches the ORDER the tasks were passed to gather, NOT the
# completion order.

Wat zal het programma uitprinten? Schrijf hier: