Predict: scope variable

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Task

📝 **Task:** Predict the output (variable scope).

```python
n = 5
def triple(n):
    n = n * 3
    return n

result = triple(n)
print(result)
print(n)
```

💡 Function parameter is a LOCAL copy. Outer `n` unchanged.

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🐍fix

Find the bug: forgotten return

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Variables

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Data types

🔮 Predict the output

Read the code carefully

n = 5
def triple(n):
    n = n * 3
    return n

result = triple(n)
print(result)
print(n)

What will the program print? Write here:

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💬 Discussion